Consider the case j=1, k=0, qn=0,. 0 consider below jk flip flop circuit and truth table: Simulation in proteus, it counts down from 0 to 9.
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Jb and kb represent the logic levels required to be applied to the j and k inputs of the 'b' flip flop to make its q output transition from its present state to its next state upon receiving a clock. Interpretation 1 one text book says: What would the logic gate diagram look like for a jk latch?
I was guessing how qn+1 column in truth table is calculated.
If i am not wrong the input is only j and k = 0 right? Let the current state of the flip be [clk = 0, j = 0, k = 1, p = 1, q = 0], this would make both s1 and r1 equal to 0, resulting in p = 1. Below are the timing diagrams which. And that's also the main reason we use a clock to.
When j = 1, k = 0, and clk (clock signal) = 1, q = 1. I followed the kmap results in the simulator but still can't get it to work. But j = 0, k = 1 should be. Given the jk flip flop below:
The first one should count even numbers:
