X.shape[0] gives the first element in that tuple, which is 10. 或者说如果我们想打印成python list，他该长成什么样子？ 假设你的np.array ()就是一个nested list, 那么它的shape,第一个值，或者说tuple第一个元素 int _0 就是对应于看你的nested list第一层有几. The shape attribute for numpy arrays returns the dimensions of the array.
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Here's a demo with some. And you can get the (number of) dimensions of your array using yourarray.ndim or np.ndim(). 8 list object in python does not have 'shape' attribute because 'shape' implies that all the columns (or rows) have equal length along certain dimension.
Yourarray.shape or np.shape() or np.ma.shape() returns the shape of your ndarray as a tuple;
Objects cannot be broadcast to a single shape it computes the first two (i am running several thousand of these tests in a loop) and then dies. Let's say list variable a has following. If y has n rows and m columns, then y.shape is (n,m). The dimensions of the array.
Please can someone tell me work of shape[0] and shape[1]? (r,) and (r,1) just add (useless) parentheses but still express respectively 1d and 2d array. In python shape[0] returns the dimension but in this code it is returning total number of set.
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