The dimensions of the array. Here's a demo with some. The shape attribute for numpy arrays returns the dimensions of the array.
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Objects cannot be broadcast to a single shape it computes the first two (i am running several thousand of these tests in a loop) and then dies. Please can someone tell me work of shape[0] and shape[1]? In python shape[0] returns the dimension but in this code it is returning total number of set.
8 list object in python does not have 'shape' attribute because 'shape' implies that all the columns (or rows) have equal length along certain dimension.
Let's say list variable a has following. If y has n rows and m columns, then y.shape is (n,m). 或者说如果我们想打印成python list，他该长成什么样子？ 假设你的np.array ()就是一个nested list, 那么它的shape,第一个值，或者说tuple第一个元素 int _0 就是对应于看你的nested list第一层有几. X.shape[0] gives the first element in that tuple, which is 10.
Yourarray.shape or np.shape() or np.ma.shape() returns the shape of your ndarray as a tuple; And you can get the (number of) dimensions of your array using yourarray.ndim or np.ndim(). (r,) and (r,1) just add (useless) parentheses but still express respectively 1d and 2d array.
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